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5x^2+45x+24=0
a = 5; b = 45; c = +24;
Δ = b2-4ac
Δ = 452-4·5·24
Δ = 1545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{1545}}{2*5}=\frac{-45-\sqrt{1545}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{1545}}{2*5}=\frac{-45+\sqrt{1545}}{10} $
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